Exploring Mth 141 D5 Implicit Differentiation Part 3

Exploring Mth 141 D5 Implicit Differentiation Part 3 reveals several interesting facts.

  • So when we do that and i'll use function notation here i guess i could just you leave it as q prime but q prime of x
  • We use the trig identity sin^2(x) = (1-cos(2x))/2 to compute a corresponding identity for cos^2(x), which we then use to build the ...

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All right so now we're done with the ... to do And then this is the point that we're interested in 1 comma square root So all

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